Raymond Hettinger <rhettin...@users.sourceforge.net> added the comment:
"We already got one, and it's very nice-a" ISTM, this should be done with regular date arithmetic in the datetime module. >>> date(1964, 7, 31) - date(1963, 12, 31) datetime.timedelta(213) I don't see why we need a new function for this or why it would be put in the calendar module (where some of its functions have been supplanted by the datetime module). ---------- nosy: +rhettinger priority: normal -> low _______________________________________ Python tracker <rep...@bugs.python.org> <http://bugs.python.org/issue9909> _______________________________________ _______________________________________________ Python-bugs-list mailing list Unsubscribe: http://mail.python.org/mailman/options/python-bugs-list/archive%40mail-archive.com
