https://github.com/python/cpython/commit/c5298705427184b0fa78d8fdee3ffba5d1bb7f73
commit: c5298705427184b0fa78d8fdee3ffba5d1bb7f73
branch: 3.13
author: Miss Islington (bot) <31488909+miss-isling...@users.noreply.github.com>
committer: picnixz <10796600+picn...@users.noreply.github.com>
date: 2025-05-17T08:05:41Z
summary:

[3.13] gh-133881: add forward reference to `list.sort()` in lambda expression 
tutorial (GH-133910) (#134127)

gh-133881: add forward reference to `list.sort()` in lambda expression tutorial 
(GH-133910)
(cherry picked from commit c1c9ad1d5a62a591eb2f0f0d29f3fa02e0949f14)

Co-authored-by: Oleg Burnaev <51371645+shepard2...@users.noreply.github.com>

files:
M Doc/tutorial/controlflow.rst

diff --git a/Doc/tutorial/controlflow.rst b/Doc/tutorial/controlflow.rst
index 8261bbdbfb7a01..b8bc94e5218087 100644
--- a/Doc/tutorial/controlflow.rst
+++ b/Doc/tutorial/controlflow.rst
@@ -998,7 +998,8 @@ scope::
    43
 
 The above example uses a lambda expression to return a function.  Another use
-is to pass a small function as an argument::
+is to pass a small function as an argument.  For instance, :meth:`list.sort`
+takes a sorting key function *key* which can be a lambda function::
 
    >>> pairs = [(1, 'one'), (2, 'two'), (3, 'three'), (4, 'four')]
    >>> pairs.sort(key=lambda pair: pair[1])

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