On Thu, 13 Jan 2005 01:04:01 -0500, Phillip J. Eby <[EMAIL PROTECTED]> wrote: > At 12:01 AM 1/13/05 -0500, Michael Walter wrote: > >What am I missing? > > The fact that this is a type-declaration issue, and has nothing to do with > *how* types are checked. I was talking about how you declare such types, sir :] (see the interface pseudo code sample -- maybe my reference to type inference lead you to think the opposite.)
> In other words, compared to the previous state of things, this should > actually require *fewer* interfaces to accomplish the same use cases, and > it doesn't require Python to have a built-in notion of "interface", because > the primitive notion is an operation, not an interface. Yepyep, but *how* you declare types now? Can you quickly type the function def f(x): x.read()? without needing an interface interface x_of_f: def read(): pass or a decorator like @foo(x.read)? I've no idea what you mean, really :o) Michael _______________________________________________ Python-Dev mailing list Python-Dev@python.org http://mail.python.org/mailman/listinfo/python-dev Unsubscribe: http://mail.python.org/mailman/options/python-dev/archive%40mail-archive.com
