At 05:15 PM 9/28/2005 +0200, Reinhold Birkenfeld wrote:
>Okay. I assume that we must accept that
>
>s = set()
>t = (s,)
>t[0] |= set([1])
>
>changes s in spite of raising TypeError.
There are lots of operations that can be partially completed before raising
an error, so I'm not sure why this case would be special.
Sets do have an update() method, however, and it's unambiguous as to being
an in-place update. The code above would be clearer using it, and produce
no errors:
s = set()
t = (s,)
t[0].update([1])
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