[Tim]
> Same top-level point, though: [for evaluating `f() and g()`]:
>
> result = f()
> if bool(result):
> result = g()
Ah, I think I see your point now. In the _context_ of `if f() and
g()`, the dumbest possible code generation would do the above, and
then go on to do
if bool(result):
....
If in fact `f()` returned a false-like value, an optimizer could note
that `bool(result)` had already been evaluated and skip the redundant
evaluation. I think that's fine either way: what the language
guarantees is that `f()` will be evaluated exactly once, and `g()` no
more than once, and that's all so regardless.
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