On Wed, Jul 4, 2018 at 12:13 PM Steven D'Aprano <st...@pearwood.info> wrote:
> On Wed, Jul 04, 2018 at 10:20:35AM -0400, David Mertz wrote:
> > Hmmm... I admit I didn't expect quite this behavior. I'm don't actually
> > understand why it's doing what it does.
> >
> > >>> def myfun():
> > ... print(globals().update({'foo', 43}), foo)
>
> Try it with a dict {'foo': 43} instead of a set :-)
> I think Chris meant to try it inside a function using locals() rather
> than globals.
Ah... you say "tomato" I say "raspberry"... set, dict...
Yeah, typo fixed, it makes more sense. Still, even a `globals().update()`
expression is a binding operation. But it works perfectly fine with
locals() also :-):
>>> def myfun():
... print(locals().update({'foo': 44}), locals().get('foo'))
...
>>> myfun()
None 44
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