Chris Angelico wrote:
Except that it does. After calling locals() a second time, the result of the *first* call will be updated to reflect changes.
Yeow. That's *really* unintuitive. There had better be an extremely good reason for this behaviour. -- Greg _______________________________________________ Python-Dev mailing list Python-Dev@python.org https://mail.python.org/mailman/listinfo/python-dev Unsubscribe: https://mail.python.org/mailman/options/python-dev/archive%40mail-archive.com
