On 22.12.2020 21:52, Alan G. Isaac wrote:
The following test fails because because `seq1 == seq2` returns a (boolean)
NumPy array
whenever either seq is a NumPy array.
You sure about that? For me, bool(np.array) raises an exception:
In [12]: np.__version__
Out[12]: '1.19.4'
In [11]: if [False, False]==np.array([False, False]): print("foo")
<...>
ValueError: The truth value of an array with more than one element is
ambiguous. Use a.any() or a.all()
import unittest
import numpy as np
unittest.TestCase().assertSequenceEqual([1.,2.,3.], np.array([1.,2.,3.]))
I expected `unittest` to rely only on features of a `collections.abc.Sequence`,
which based on https://docs.python.org/3/glossary.html#term-sequence,
I believe are satisfied by a NumPy array. Specifically, I see no requirement
that a sequence implement __eq__ at all much less in any particular way.
In short: a test named `assertSequenceEqual` should, I would think,
work for any sequence and therefore (based on the available documentation)
should not depend on the class-specific implementation of __eq__.
Is that wrong?
Thank you, Alan Isaac
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--
Regards,
Ivan
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