On Fri, Sep 29, 2006 at 12:03:03PM -0700, Guido van Rossum wrote: > I see some confusion in this thread. > > If a *LITERAL* 0.0 (or any other float literal) is used, you only get > one object, no matter how many times it is used.
For some reason that doesn't happen in the interpreter which has been confusing the issue slightly... $ python2.5 Python 2.5c1 (r25c1:51305, Aug 19 2006, 18:23:29) [GCC 4.1.2 20060814 (prerelease) (Debian 4.1.1-11)] on linux2 Type "help", "copyright", "credits" or "license" for more information. >>> a=0.0 >>> b=0.0 >>> id(a), id(b) (134737756, 134737772) >>> $ python2.5 -c 'a=0.0; b=0.0; print id(a),id(b)' 134737796 134737796 > But if the result of a *COMPUTATION* returns 0.0, you get a new object > for each such result. If you have 70 MB worth of zeros, that's clearly > computation results, not literals. In my application I'm receiving all the zeros from a server over TCP as ASCII and these are being float()ed in python. -- Nick Craig-Wood <[EMAIL PROTECTED]> -- http://www.craig-wood.com/nick _______________________________________________ Python-Dev mailing list Python-Dev@python.org http://mail.python.org/mailman/listinfo/python-dev Unsubscribe: http://mail.python.org/mailman/options/python-dev/archive%40mail-archive.com
