Probably because I tend not to know what I'm doing when numerics are concerned. :-(
On 1/19/07, Raymond Hettinger <[EMAIL PROTECTED]> wrote: > I bumped into an oddity today: > > 6.0 // 0.001 != math.floor(6.0 / 0.001) > > In looking at Objects/floatobject.c, I was surprised to find that > float_floor_division() is implemented in terms of float_divmod(). Does anyone > know why it takes such a circuitous path? I had expected something simpler > and > faster: > > return PyFloat_FromDouble(floor(a/b)); > > > Raymond > > _______________________________________________ > Python-Dev mailing list > Python-Dev@python.org > http://mail.python.org/mailman/listinfo/python-dev > Unsubscribe: > http://mail.python.org/mailman/options/python-dev/guido%40python.org > -- --Guido van Rossum (home page: http://www.python.org/~guido/) _______________________________________________ Python-Dev mailing list Python-Dev@python.org http://mail.python.org/mailman/listinfo/python-dev Unsubscribe: http://mail.python.org/mailman/options/python-dev/archive%40mail-archive.com
