You can create a frozenset from any iterable using PyFrozenSet_New().
If you don't have an iterable and want to build-up the frozenset one element at
a time, the approach is to create a regular set (or some other mutable
container), add to it, then convert it to a frozenset when you're done:
s = PySet_New(NULL);
PySet_Add(s, obj1);
PySet_Add(s, obj2);
PySet_Add(s, obj3);
f = PyFrozenSet_New(s);
Py_DECREF(s);
That approach is similar to what you do with tuples in pure python. You either
build them from an iterable "t = tuple(iterable)" or your build-up a mutable
object one element at a time and convert it all at once:
s = []
s.append(obj1)
s.append(obj2)
t = tuple(s)
The API you propose doesn't work because sets and frozensets are not indexed
like tuples and lists. Accordingly, sets and frozensets have a C API that is
more like dictionaries. Since dictionaries are not indexable, they also cannot
have an API like the one you propose:
PyDict_NEW(int) => PySetObject *
PyDict_SET_ITEM(s, index, key, value)
If you find all this really annoying and need to fashion a small frozenset with
a few known objects, consider using the abstract API:
f = PyObject_CallFunction(&PyFrozenSet_Type, "(OOO)", obj1, obj2, obj3);
That will roll the whole process up into one line.
Hope this was helpful,
Raymond
---------------------------------------------------------------
Bill Janssen <[EMAIL PROTECTED]>Add To Address Book|This is Spam
Subject:[Python-Dev] frozenset C API?
To:[email protected]
I'm looking at building a "frozenset" instance as a return value from
a C function, and the C API seems ridiculously clumsy. Maybe I'm
misunderstanding it. Apparently, I need to create a list object, then
pass that to PyFrozenSet_New(), then decref the list object.
Is that correct?
What I'd like is something more like
PyFrozenSet_NEW(int) => PySetObject *
PyFrozenSet_SET_ITEM(s, i, v)
Any idea why these aren't part of the API?
_______________________________________________
Python-Dev mailing list
[email protected]
http://mail.python.org/mailman/listinfo/python-dev
Unsubscribe:
http://mail.python.org/mailman/options/python-dev/archive%40mail-archive.com
