Phillip J. Eby wrote: > At 09:30 PM 12/30/2008 -0500, rdmur...@bitdance.com wrote: >> On Tue, 30 Dec 2008 at 17:51, Phillip J. Eby wrote: >>> At 02:32 PM 12/30/2008 -0800, Scott David Daniels wrote: >>>> More trouble with the "just take the dirname": >>>> >>>> paths = ['/a/b/c', '/a/b/d', '/a/b'] >>>> os.path.dirname(os.path.commonprefix([ >>>> os.path.normpath(p) for p in paths])) >>>> give '/a', not '/a/b'. >>> >>> ...because that's the correct answer. >> >> But not the answer that is wanted. >> >> So the challenge now is to write a single expression that will yield >> '/a/b' when passed the above paths list, and also produce '/a/b' when >> passed the following paths list: >> >> paths = ['/a/b/c', '/a/b/cd'] > > Change that to [os.path.normpath(p)+'/' for p in paths] and you've got > yourself a winner. > Or possibly [os.path.normpath(p)+os.path.sep for p in paths]?
regards Steve -- Steve Holden +1 571 484 6266 +1 800 494 3119 Holden Web LLC http://www.holdenweb.com/ _______________________________________________ Python-Dev mailing list Python-Dev@python.org http://mail.python.org/mailman/listinfo/python-dev Unsubscribe: http://mail.python.org/mailman/options/python-dev/archive%40mail-archive.com
