Hi, recently I wrote an algorithm, in which very often I had to get an arbitrary element from a set without removing it.
Three possibilities came to mind: 1. x = some_set.pop() some_set.add(x) 2. for x in some_set: break 3. x = iter(some_set).next() Of course, the third should be the fastest. It nevertheless goes through all the iterator creation stuff, which costs some time. I wondered, why the builtin set does not provide a more direct and efficient way for retrieving some element without removing it. Is there any reason for this? I imagine something like x = some_set.get() or x = some_set.pop(False) and am thinking about providing a patch against setobject.c (preferring the .get() solution being a stripped down pop()). Before, I would like to know whether I have overlooked something or whether this can be done in an already existing way. Thanks, wr _______________________________________________ Python-Dev mailing list Python-Dev@python.org http://mail.python.org/mailman/listinfo/python-dev Unsubscribe: http://mail.python.org/mailman/options/python-dev/archive%40mail-archive.com