Curt Hagenlocher wrote:

Wait, what? I haven't been paying much attention, but this is backwards.
There are multiple representations of NaN in the IEEE encoding;

I think Nick's point is that there aren't enough bits
to give the result of every operation its own unique
NaN.

The payload of a NaN in typical hardware implementations
is quite small, because it has to fit into the exponent
field.

--
Greg
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