On Wed, May 18, 2011 at 2:21 PM, Victor Stinner
<victor.stin...@haypocalc.com> wrote:
> ''.join(c for c in 'abc') and ''.join([c for c in 'abc']) do create a
> temporary c variable.
I'm not sure why you would encounter code like that in the first place.
Surely any code of the form:
''.join(c for c in my_string)
would just return my_string? Or am I missing something?
> I heard about optimization in the AST tree instead of working on the
> bytecode. What is the status of this project?
Are you referring to issue11549? There was some related discussion [1] on
python-dev about six weeks ago, but I haven't seen anything on the topic
since then.
Cheers,
Nadeem
[1] http://mail.python.org/pipermail/python-dev/2011-April/110399.html
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