Łukasz Langa, 19.05.2011 11:25:
Wiadomość napisana przez Stefan Behnel w dniu 2011-05-19, o godz. 10:37:
But why wouldn't "they" expect `b'de' + 1` to work as well in this case? If a
1-byte bytes is equivalent to an integer, why not an arbitrary one as well?
The result of this must obviously be b"de1".
I hope you're joking.
I "obviously" was. My point is that expectations and "obvious behaviour"
may not be obvious to everyone.
Nick summed it up very nicely IMHO.
Stefan
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