On Fri, Jan 6, 2012 at 10:07 AM, Steven D'Aprano <st...@pearwood.info> wrote:
> Surely the way to verify the behaviour is to run this from the shell:
>
> python -c print(hash("abcde"))
>
> twice, and see that the calls return different values. (Or have I
> misunderstood the way the fix is going to work?)
>
> In any case, I wouldn't want to rely on the presence of a flag in the sys
> module to verify the behaviour, I'd want to see for myself that hash
> collisions are no longer predictable.
More directly, you can just check that the hash of the empty string is non-zero.
So -1 for a flag in the sys module - "hash('') != 0" should serve as a
sufficient check whether or not process-level string hash
randomisation is in effect.
Cheers,
Nick.
--
Nick Coghlan | ncogh...@gmail.com | Brisbane, Australia
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