01.03.12 11:11, Victor Stinner написав(ла):
You can redefine dict.__setitem__.
Ah? It doesn't work here.

dict.__setitem__=lambda key, value: None
Traceback (most recent call last):
   File "<stdin>", line 1, in<module>
TypeError: can't set attributes of built-in/extension type 'dict'

Hmm, yes, it's true. It was too presumptuous of me to believe that you have not considered such simple approach.

But I will try to suggest another approach. `frozendict` inherits from `dict`, but data is not stored in the parent, but in the internal dictionary. And even if dict.__setitem__ is used, it will have no visible effect.

  class frozendict(dict):
      def __init__(self, values={}):
          self._values = dict(values)
      def __getitem__(self, key):
          return self._values[key]
      def __setitem__(self, key, value):
          raise TypeError ("expect dict, got frozendict")
      ...


 >>> a = frozendict({1: 2, 3: 4})
 >>> a[1]
 2
 >>> a[5]
   Traceback (most recent call last):
   File "<stdin>", line 1, in <module>
   File "<stdin>", line 5, in __getitem__
 KeyError: 5
 >>> a[5] = 6
 Traceback (most recent call last):
   File "<stdin>", line 1, in <module>
   File "<stdin>", line 7, in __setitem__
 TypeError: expect dict, got frozendict
 >>> dict.__setitem__(a, 5, 6)
 >>> a[5]
 Traceback (most recent call last):
   File "<stdin>", line 1, in <module>
   File "<stdin>", line 5, in __getitem__
 KeyError: 5

_______________________________________________
Python-Dev mailing list
Python-Dev@python.org
http://mail.python.org/mailman/listinfo/python-dev
Unsubscribe: 
http://mail.python.org/mailman/options/python-dev/archive%40mail-archive.com

Reply via email to