On 12.09.12 00:47, Victor Stinner wrote:
x = x + [y] => x.append(y)
x = x + [y, z] => x.extend([y, z])
It behaves differently if x is not a list, but str for example.
Actually even worse. Transformations applicable only if x has not
aliases. Pseudocode:
if type(x) is list and refcount(x) == 1:
list.append(x, y)
else:
x = x + [y]
This optimization can be done only in the interpreter, otherwise
overhead costs will be too high.
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