On Fri, Feb 8, 2013 at 5:44 PM, Stefan Behnel <stefan...@behnel.de> wrote: > Argh - sorry, got it all wrong. "__instancecheck__()" works exactly the > other way round. In the type check above, it's the FunctionType type that > gets asked for an instance check, which doesn't help at all in this case > because it simply doesn't know about the desired subtype relation. It would > work if type(func).__instancecheck__() was used, but that doesn't happen. > > So, no help from that side, sadly.
How about you return FunctionType as your __class__ attribute? ;-) Your type() will still be different, but isinstance() also considers the __class__ if it's different from the type(). (At least it does in 2.x, I've not tried it in any 3.x versions yet...) _______________________________________________ Python-Dev mailing list Python-Dev@python.org http://mail.python.org/mailman/listinfo/python-dev Unsubscribe: http://mail.python.org/mailman/options/python-dev/archive%40mail-archive.com
