On 06/17/2013 12:04 PM, Walter Dörwald wrote:
Making the string raw, of course turns it into:
U+0027: APOSTROPHE
U+0027: APOSTROPHE
U+0027: APOSTROPHE
U+005C: REVERSE SOLIDUS
U+0072: LATIN SMALL LETTER R
U+005C: REVERSE SOLIDUS
U+006E: LATIN SMALL LETTER N
U+0027: APOSTROPHE
U+0027: APOSTROPHE
U+0027: APOSTROPHE
and eval()ing that does indeed give "\r\n" as expected.
You can also escape the reverse slashes in a regular string to get the same
result.
>>> s1 = "'''\\r\\n'''"
>>> list(s1)
["'", "'", "'", '\\', 'r', '\\', 'n', "'", "'", "'"]
>>> s2 = eval(s1)
>>> list(s2)
['\r', '\n']
>>> s3 = "'''%s'''" % s2
>>> list(s3)
["'", "'", "'", '\r', '\n', "'", "'", "'"]
>>> s4 = eval(s3)
>>> list(s4)
['\n']
When a standard string literal used with eval, it's evaluated first to a
string object in the same scope as the eval function is called from, then
the eval function is called with that string object and it's evaluated
again. So it's really being parsed twice. (That's the part that got me.)
The transformation between s1 and s2 is what Phillip is referring to, and
Guido is referring to the transformation from s2 to s4. (s3 is needed to
avoid the end of line error of evaluating a single quoted string with \n in
it.)
When a sting literal is used directly with eval, it looks like it is
evaluated from s1 to s4 in one step, but that isn't what is happening.
Cheers, Ron
(ps: Was informed my posts where showing up twice.. hopefully I got that
fixed now.)
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