Perfect, thanks!
On Sun, Jan 25, 2015 at 7:08 AM, Petr Viktorin <encu...@gmail.com> wrote:
> On Sun, Jan 25, 2015 at 12:55 PM, Neil Girdhar <mistersh...@gmail.com>
> wrote:
> > How do I disassemble a generated comprehension?
> >
> > For example, I am trying to debug the following:
> >
> >>>> dis.dis('{**{} for x in [{1:2}]}')
> > 1 0 LOAD_CONST 0 (<code object <dictcomp> at
> > 0x10160b7c0, file "<dis>", line 1>)
> > 3 LOAD_CONST 1 ('<dictcomp>')
> > 6 MAKE_FUNCTION 0
> > 9 LOAD_CONST 2 (2)
> > 12 LOAD_CONST 3 (1)
> > 15 BUILD_MAP 1
> > 18 BUILD_LIST 1
> > 21 GET_ITER
> > 22 CALL_FUNCTION 1 (1 positional, 0 keyword pair)
> > 25 RETURN_VALUE
> >
> > (This requires the new patch in issue 2292.)
> >
> > The code here looks fine to me, so I need to look into the code object
> > <dictcomp>. How do I do that?
>
> Put it in a function, then get it from the function's code's constants.
> I don't have the patch applied but it should work like this even for
> the new syntax:
>
> >>> import dis
> >>> def f(): return {{} for x in [{1:2}]}
> ...
> >>> dis.dis(f)
> 1 0 LOAD_CONST 1 (<code object <setcomp> at
> 0x7ff2c0647420, file "<stdin>", line 1>)
> 3 LOAD_CONST 2 ('f.<locals>.<setcomp>')
> 6 MAKE_FUNCTION 0
> 9 BUILD_MAP 1
> 12 LOAD_CONST 3 (2)
> 15 LOAD_CONST 4 (1)
> 18 STORE_MAP
> 19 BUILD_LIST 1
> 22 GET_ITER
> 23 CALL_FUNCTION 1 (1 positional, 0 keyword pair)
> 26 RETURN_VALUE
> >>> f.__code__.co_consts[1] # from "LOAD_CONST 1"
> <code object <setcomp> at 0x7ff2c0647420, file "<stdin>", line 1>
> >>> dis.dis(f.__code__.co_consts[1])
> 1 0 BUILD_SET 0
> 3 LOAD_FAST 0 (.0)
> >> 6 FOR_ITER 12 (to 21)
> 9 STORE_FAST 1 (x)
> 12 BUILD_MAP 0
> 15 SET_ADD 2
> 18 JUMP_ABSOLUTE 6
> >> 21 RETURN_VALUE
>
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