On 04.02.2016 16:57, Matthias Bussonnier wrote:
On Feb 3, 2016, at 13:22, Yury Selivanov <yselivanov...@gmail.com> wrote:
An ideal way would be to calculate a hit/miss ratio over time
for each cached opcode, but that would be an expensive
calculation.
Do you mean like a sliding windows ?
Otherwise if you just want a let's say 20% miss threshold, you increment by 1
on hit,
and decrement by 4 on miss.
Division is expensive.
On Feb 3, 2016, at 13:37, Sven R. Kunze <srku...@mail.de> wrote:
On 03.02.2016 22:22, Yury Selivanov wrote:
One way of tackling this is to give each optimized opcode
a counter for hit/misses. When we have a "hit" we increment
that counter, when it's a miss, we decrement it.
Within a given range, I suppose. Like:
c = min(c+1, 100)
Min might be overkill, maybe you can use a or mask, to limit the windows range
to 256 consecutive call ?
Sure, that is how I would have written it in Python. But I would suggest
an AND mask. ;-)
Best,
Sven
_______________________________________________
Python-Dev mailing list
Python-Dev@python.org
https://mail.python.org/mailman/listinfo/python-dev
Unsubscribe:
https://mail.python.org/mailman/options/python-dev/archive%40mail-archive.com
