Te paso mi setup.py:
manifest = """
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<!-- Copyright (c) Microsoft Corporation. All rights reserved. -->
<assembly xmlns="urn:schemas-microsoft-com:asm.v1" manifestVersion="1.0">
<noInheritable/>
<assemblyIdentity
type="win32"
name="Microsoft.VC90.CRT"
version="9.0.21022.8"
processorArchitecture="x86"
publicKeyToken="1fc8b3b9a1e18e3b"
/>
<file name="msvcr90.dll" />
</assembly>
"""
from distutils.core import setup
import py2exe
from glob import glob
class Target:
def __init__(self, **kw):
self.__dict__.update(kw)
# for the versioninfo resources
self.version = "1.0"
self.company_name = "AUTOR"
self.copyright = "AUTOR"
self.name = "puntos"
ssystem = Target(
# used for the versioninfo resource
description = "puntos",
# what to build
script = "puntos.py",
icon_resources = [(1, "./images/icon.ico")],
dest_base = "puntos")
setup(
options = {"py2exe": {"compressed": 1,
"optimize": 0,
"bundle_files": 1,
}},
data_files = [
("Microsoft.VC90.CRT", glob(r'C:\Microsoft.VC90.CRT\*.*')),
#dentro de la carpeta Microsoft.VC90.CRT tengo un ficheero llamado
Microsoft.VC90.CRT.manifest y otro llamado msvcr90.dll
'./preferencias.ini',
],
zipfile = None,
windows = [ssystem]
)
En 2010/07/09 18:29, Jean Carlos Rodrìguez escribiu:
Hola les comento estoy haciendo un ejecutable con py2exe,
from distutils.core import setup
import py2exe
import sys
sys.argv.append('py2exe')
setup(windows = [
{
"script": "nombre.py",
"icon_resources": [(1, "Icono/icono.ico")]
}
],
options={"py2exe":{"includes":["sip"],
}}
)
Es el mismo script que utilizaba en las versiones anteriores de python, este me
realiza el ejcutable y cuando le doy doble click, no hace nada ni me error, uso
python 2.6.5
PyQt-Py2.6-gpl-4.7-1
py2exe-0.6.9.win32-py2.6
Gracias
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