Abe-
You are correct. However I think it may still be salvageable.
In your code example, you could be either making a dict with a key of 1, or a
set of a delayed object. But there's no reason to build a set of a delayed
object because hashing it would immediately un-delay.
Similarly, I am not sure delayed should be allowed inside of function headers.
So we could say that dictionary keys and sets shouldn't be allowed to use the
delayed keyword. Same with function headers. Are there any other collisions?
-Joseph
On Feb 17, 2017, at 3:41 PM, Abe Dillon <abedil...@gmail.com> wrote:
>> Couldn't the same thing be true of delayed if it is always followed by a
>> colon?
>
> No. Because there are other reasons you'd follow the variable `delayed` with
> a colon:
>
> >>> delayed = 1
> >>> d = {delayed: "oops!"}
>
> My earlier proposal (using unpacking syntax) doesn't work for the same
> reason.
>
>> On Fri, Feb 17, 2017 at 2:31 PM, Joseph Hackman <josephhack...@gmail.com>
>> wrote:
>> Couldn't the same thing be true of delayed if it is always followed by a
>> colon?
>>
>> I.e.
>> delayed=1
>> x= delayed: slow_function()
>> print(delayed) # prints 1
>>
>> -Joseph
>>
>>> On Feb 17, 2017, at 2:39 PM, Mark E. Haase <meha...@gmail.com> wrote:
>>>
>>>> On Fri, Feb 17, 2017 at 1:55 PM, Joshua Morton <joshua.morto...@gmail.com>
>>>> wrote:
>>>> but I'm wondering how common async and await were when that was proposed
>>>> and accepted?
>>>
>>>
>>> Actually, "async" and "await" are backwards compatible due to a clever
>>> tokenizer hack. The "async" keyword may only appear in a few places (e.g.
>>> async def), and it is treated as a name anywhere else.The "await" keyword
>>> may only appear inside an "async def" and is treated as a name everywhere
>>> else. Therefore...
>>>
>>> >>> async = 1
>>> >>> await = 1
>>>
>>> ...these are both valid in Python 3.5. This example is helpful when
>>> proposing new keywords.
>>>
>>> More info: https://www.python.org/dev/peps/pep-0492/#transition-plan
>>>
>>>
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