Hi Wolfram
You tried
> def f(a):
> .. print(a)
> f(**{"a":2})
> 2
> f(**{"a+1":2})
> Traceback (most recent call last):
> File "python", line 1, in <module>
> TypeError: f() got an unexpected keyword argument 'a+1'
This is exactly what I would have expected. Please consider the following:
>>> def f(a): pass
>>> f(**dict(b=1))
TypeError: f() got an unexpected keyword argument 'b'
> Does CPython count as "other python implementation"?
Yes and No. Both are half correct. CPython is the reference
implementation. Please also consider
>>> def f(a, **kwargs): pass
>>> f(a=1, **{'a+1': 2})
>>> f(a=1, **{(0, 1): 2})
TypeError: f() keywords must be strings
So far as I know, that a keyword be a string is the only constraint,
at least in CPython. For example
>>> def f(a, **kwargs): pass
>>> f(a=1, **{'': 2})
>>> f(a=1, **{'def': 2})
So I think Anders proposal works in CPython. I think you forgot the
**kwargs in the parameters to f.
best regards
Jonathan
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