On 2019-02-02 17:31, Adrien Ricocotam wrote:
> I personally would the first option to be the case. But then vectors
shouldn't be list-like but more generator like.
>
OK, here's another one: if you use 'list(...)' on a vector, does it
apply to the vector itself or its members?
>>> list(my_strings)
You might be wanting to convert a vector into a list:
['one', 'two', 'three']
or convert each of its members onto lists:
Vector([['one'], ['two'], ['three']])
> Le sam. 2 févr. 2019 à 19:26, MRAB <pyt...@mrabarnett.plus.com> a écrit :
>
> On 2019-02-02 09:22, Kirill Balunov wrote:
> >
> >
> > сб, 2 февр. 2019 г. в 07:33, Steven D'Aprano <st...@pearwood.info
> > <mailto:st...@pearwood.info>>:
> >
> >
> > I didn't say anything about a vector type.
> >
> >
> > I agree you did not say. But since you started a new thread
from the
> > one where the vector type was a little discussed, it seemed to
me that
> > it is appropriate to mention it here. Sorry about that.
> >
> > > Therefore, it allows you to ensure that the method is
present for
> > each
> > > element in the vector. The first given example is what
numpy is
> > all about
> > > and without some guarantee that L consists of
homogeneous data it
> > hardly
> > > make sense.
> >
> > Of course it makes sense. Even numpy supports inhomogeneous
data:
> >
> > py> a = np.array([1, 'spam'])
> > py> a
> > array(['1', 'spam'],
> > dtype='|S4')
> >
> >
> > Yes, numpy, at some degree, supports heterogeneous arrays. But
not in
> > the way you brought it. Your example just shows homogeneous
array of
> > type `'|S4'`. In the same way as `np.array([1, 1.234])` will be
> > homogeneous. Of course you can say - np.array([1, 'spam'],
> > dtype='object'), but in this case it will also be homogeneous
array, but
> > of type `object`.
> >
> > Inhomogeneous data may rule out some optimizations, but
that hardly
> > means that it "doesn't make sense" to use it.
> >
> >
> > I did not say that it "doesn't make sense". I only said that
you should
> > be lucky to call `..method()` on collections of heterogeneous
data. And
> > therefore, usually this kind of operations imply that you are
working
> > with a "homogeneous data". Unfortunately, built-in containers
cannot
> > provide such a guarantee without self-checking. Therefore, in
my opinion
> > that at the moment such an operator is not needed.
> >
> Here's a question: when you use a subscript on a vector, does it
apply
> to the vector itself, or its members?
>
> For example, given:
>
> >>> my_strings = Vector(['one', 'two', 'three'])
>
> what is:
>
> >>> my_strings[1 : ]
>
> ?
>
> Is it:
>
> Vector(['ne', 'wo', 'hree'])
>
> or:
>
> Vector(['two', 'three'])
>
> ?
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