And if you can't / don't want to create new lists for the values you
want to compare, a solution could be to use zip & all builtins:
print(all(a == b for a, b in zip(tuple_, list_)))
Le sam. 2 mai 2020 à 16:58, Steele Farnsworth <swfarnswo...@gmail.com> a écrit :
>
> You can get the desired behavior by casting a list to a tuple, or a tuple to
> a list, in the equality statement. That way those that rely on the existing
> implementation don't have to change their code.
>
> my_tup = (1, 2, 3)
> my_list = [1, 2, 3]
> print(list(my_tup) == my_list)
>
> On Sat, May 2, 2020, 9:04 AM Ahmed Amr <ahmedam...@gmail.com> wrote:
>>
>> I'd like to take your opinion on modifying some of the indexed collections
>> like tuples, lists, arrays to evaluate its equality to True when having the
>> same items in the same indexes.
>> Currently, when comparing a list of items to an array of the same items for
>> equality (==) it returns False, I'm thinking that it would make sense to
>> return True in that context, as we're comparing item values and we have the
>> same way of indexing both collections, so we can compare item values.
>>
>> So what do you think about applying such behavior on collections that can be
>> indexed the same way such as tuples, lists, and arrays?
>>
>> Example: (Current)
>>
>> import array
>> tuple_ = (1.1, 2.2, 3.3)
>> list_ = [1.1, 2.2, 3.3]
>> array_ = array.array('f', [1.1, 2.2, 3.3])
>>
>> # all of the following prints False.
>> print(tuple_ == list_)
>> print(tuple_ == array_)
>> print(array_ == list_)
>>
>> Example: (Proposed):
>> All prints above to show True as they are populated with the same data in
>> the same indexes.
>>
>> A Side Note:
>> An extra point to discuss, based on arrays implementation, array_.to_list()
>> would actually get [1.100000023841858, 2.200000047683716, 3.299999952316284]
>> which is not exactly what we've passed as args and this is normal, but I'm
>> thinking about leaving it to the array implementation to encapsulate that
>> implementation and perform exact equality based on passed arguments.
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Antoine Rozo
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