On Thu, Dec 17, 2020 at 03:52:51PM +0300, Paul Sokolovsky wrote:
> But I did by now, and you didn't need to wait for me to do it, because
> "(a.b)()" does *exactly* what *you* or anybody else would think it
> does, based on your knowledge of what grouping parens in the
> expressions do. So again, "(a.b)()" first extracts a value of the "b"
> *attribute* from the object held in variable "a", then calls that
> value with 0 arguments.
>
> That's in striking difference to "a.b()", which calls the *method* "b"
> of object held in variable "a".
In CPython, both generate exactly the same byte-code, and both will call
any sort of object. Or *attempt* to call, since there is no guarantee
that the attribute returned by `a.b` (with or without parens) will be a
callable object.
You are imagining differences in behaviour which literally do not exist.
```
>>> dis.dis('a.b()')
1 0 LOAD_NAME 0 (a)
2 LOAD_METHOD 1 (b)
4 CALL_METHOD 0
6 RETURN_VALUE
>>> from types import SimpleNamespace
>>> a = SimpleNamespace()
>>> a.b = int
>>> a.b("123")
123
```
--
Steve
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