Actually you can get the cache data from the python version, for that you
need to force the use of the python version of functools
def get_cache(f):
freevars = f.__code__.co_freevars
index = freevars.index('cache')
return f.__closure__[index].cell_contents
import importlib.abc
class ForcePythonLruCache(importlib.abc.MetaPathFinder):
def find_spec(self, fullname, path, target=None):
if fullname == '_functools':
raise ImportError('_functools not available')
import sys
del sys.modules['functools']
del sys.modules['_functools']
import functools
@functools.lru_cache
def test(x):
return x
test(1)
test(2)
test('a')
test('foo')
print(list(get_cache(test).keys()))
On Tue, Jan 12, 2021 at 4:09 PM Paul Moore <p.f.mo...@gmail.com> wrote:
> On Tue, 12 Jan 2021 at 17:16, Christopher Barker <python...@gmail.com>
> wrote:
> >
> > Is the implementation of lru_cache too opaque to poke into it without an
> existing method? Or write a quick monkey-patch?
> >
> > Sorry for not checking myself, but the ability to do that kind of thing
> is one of the great things about a dynamic open source language.
>
> I've only looked at the Python implementation, but the cache is a
> local variable in the wrapper, unavailable from outside. The cache
> information function is a closure that references that local variable,
> assigned as an attribute of the wrapped function.
>
> It's about as private as it's possible to get in Python (not
> particularly because it's *intended* to hide anything, as far as I can
> tell, more likely for performance or some other implementation
> reason).
>
> Paul
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--
Sebastian Kreft
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