> On 18 Mar 2021, at 11:07, Maxime Mouchet <maxime.mouc...@lip6.fr> wrote:
>
> Hi,
>
> Python supports IPv4-mapped IPv6 addresses as defined by RFC 4038:
> "the IPv6 address ::FFFF:x.y.z.w represents the IPv4 address x.y.z.w.”
>
> The current behavior is as follows:
>
> from ipaddress import ip_address
> addr = ip_address('::ffff:8.8.4.4') # IPv6Address('::ffff:808:404')
> addr.ipv4_mapped # IPv4Address('8.8.4.4')
>
> Note that the textual representation of the IPv6Address is *not* in
> IPv4-mapped format.
> It prints ::ffff:808:404 instead of ::ffff:8.8.4.4.
> This is technically correct, but it’s somewhat frustrating as it makes it
> harder to read IPv4s embedded in IPv6 addresses.
>
> My proposal would be to check, in __str__, if an IPv6 is an IPv4-mapped, and
> to return the appropriate representation :
>
> from ipaddress import ip_address
> addr = ip_address('::ffff:8.8.4.4')
>
> # Current behavior
> str(addr) # '::ffff:808:404'
> repr(addr) # IPv6Address('::ffff:808:404')
>
> # Proposed behavior
> str(addr) # '::ffff:8.8.4.4'
> repr(addr) # IPv6Address('::ffff:8.8.4.4')
>
> A few data points:
> - Julia prints ::ffff:808:404 (current behavior)
> - C (glibc) and ClickHouse prints ::ffff:8.8.4.4 (proposed behavior)
>
> Any thoughts?
This looks like a reasonable request (as someone that’s not the ipaddr
maintainer and doesn’t really use IPv6). Could you file an issue about this?
Ronald
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