Not to go off on too much of a tangent, but isn't NaN unorderable?  Its
greater than nothing, and less than nothing, so you can't even really sort a
list with a NaN value in it (..though I'm sure python does sort it by some
metric for practical reasons) - it would be impossible to find a NaN with a
binary search... it would be impossible to have a NaN in an ordered sequence
.... wouldn't it?

-----Original Message-----
From: Cameron Simpson <c...@cskk.id.au> 
Sent: Sunday, August 29, 2021 5:36 PM
To: python-ideas@python.org
Subject: [Python-ideas] Re: NAN handling in statistics functions

On 27Aug2021 15:50, Finn Mason <finnjavie...@gmail.com> wrote:
>Perhaps a math.hasnan() function for collections could be implemented 
>with binary search?
>
>math.hasnan(seq)

Why would a binary search be of use? A staraight sequential scan of the
sequence seems the only reliable method. Binary search is for finding a
value in an ordered sequence.

Cheers,
Cameron Simpson <c...@cskk.id.au>
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