Will we be able to splat/unpack the `?`?
>>> args = get_starting_list_values()
>>> args
(1, 2, 3)
>>> dd = defaultdict([*?])
>>> dd["spam"]
[1, 2, 3]
or:
>>> kwargs = get_kwargs()
>>> kwargs
{'x': 1, 'y' 2, 'z': 3}
>>> dd = defaultdict(Node(**?))
>>> dd["eggs"]
Node(x=1, y=2, z=3)
---
Ricky.
"I've never met a Kentucky man who wasn't either thinking about going home
or actually going home." - Happy Chandler
On Wed, Sep 29, 2021 at 9:03 AM Chris Angelico <ros...@gmail.com> wrote:
> On Wed, Sep 29, 2021 at 10:56 PM Dominik Vilsmeier
> <dominik.vilsme...@gmx.de> wrote:
> > members.sort(key=(?[1], ?[0]))
>
> How do you know whether this is one function that returns a tuple, or
> a tuple of two functions?
>
> ChrisA
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