On Tue, 18 Jul 2023 at 19:02, Dom Grigonis <dom.grigo...@gmail.com> wrote:
>
> Thank you.
>
> I meant “superset of 671, not 505”…
>
> One question:
>
> def bar(a => None);
> return foo(a)
>
> def foo(a => object()):
> return a
>
> How would I force foo’s default from bar’s call?
That's a known-hard problem. The best way is probably to use *a,**kw
and only pass the args you get, but that doesn't always work.
> Would something like this work?
>
> def foo(a => object() if a is None else a):
> return a
Yyyyyyes, but now you're defining that a could be None, so you may as
well go with the classic idiom:
def foo(a=None):
if a is None: a = object()
The point of default argument expressions is that you DON'T need to
accept a fake default.
ChrisA
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