Ok, this is tricky. So pretty much impossible, given that `Break`, if it was to work has to be evaluated in reference scope, while other delayed objects in their definition scope.
---------------------- Back to deferred evaluation. ---------------------- Giving it a rest for a while. Thank you for your patience. > On 20 Jul 2023, at 12:38, Chris Angelico <ros...@gmail.com> wrote: > > On Thu, 20 Jul 2023 at 19:34, Dom Grigonis <dom.grigo...@gmail.com> wrote: >> And ideally, adding 2 builtin(or imported from stdlib) functions: `Break` >> and `Continue`, which if called act as `break` and `continue` statements. >> > > How would they work? Would every function call have to provide the > possibility to return to a location that wasn't where you would > otherwise go? > > if random.randrange(2): > func = Break > else: > def func(): pass > > def wut(): > for i in range(1, 10): > if i % 3: func() > print(i) > > wut() > > Please, tell me how this would behave. > > ChrisA _______________________________________________ Python-ideas mailing list -- python-ideas@python.org To unsubscribe send an email to python-ideas-le...@python.org https://mail.python.org/mailman3/lists/python-ideas.python.org/ Message archived at https://mail.python.org/archives/list/python-ideas@python.org/message/RTKFGBNVJ2UQSMFTFNAHFB7HS674GI4B/ Code of Conduct: http://python.org/psf/codeofconduct/
