> I'm a little confused as to what you're trying to do here. The f() > function, in particular, doesn't make much sense
I see I am misunderstood. The example was contrived, and it seems, incorrect. I simulate threads, using generator functions and a scheduler. My implementation lives here: http://metaplay.com.au/svn/LGT/LGT/nanothreads.py If the same functions were to run inside a normal thread, they would need to loop forever, rather than yield None on each iteration. I see now that replacing return with yield won't work, a yield instruction needs to be inserted somewhere. I guess this changes my question to: Can I convert a function containing an infinite loop, into a generator which will yield on each iteration? Sw. -- http://mail.python.org/mailman/listinfo/python-list
