[EMAIL PROTECTED] (Roy Smith) writes:
> I've got a silly little problem that I'm solving in C++, but I got to
> thinking about how much easier it would be in Python. Here's the
> problem:
>
> You've got a list of words (actually, they're found by searching a
> data structure on the fly, but for now let's assume you've got them as
> a list). You need to create a comma-delimited list of these words.
> There might be duplicates in the original list, which you want to
> eliminate in the final list. You don't care what order they're in,
> except that there is a distinguised word which must come first if it
> appears at all.
>
> Some examples ("foo" is the distinguised word):
>
> ["foo"] => "foo"
> ["foo", "bar"] => "foo, bar"
> ["bar", "foo"] => "foo, bar"
> ["bar", "foo", "foo", "baz", "bar"] => "foo, bar, baz" or "foo, baz, bar"
>
> The best I've come up with is the following. Can anybody think of a
> simplier way?
...
How about:
.>>> words = ["foo", "bar", "baz", "foo", "bar", "foo", "baz"]
.>>> ', '.join(dict( ( (w,w) for w in words ) ).keys())
'baz, foo, bar'
.>>> words = ["foo",]
.>>> ', '.join(dict( ( (w,w) for w in words ) ).keys())
'foo'
or with Python 2.3 or higher:
.>>> import sets
.>>> words = ["foo", "bar", "baz", "foo", "bar", "foo", "baz"]
.>>> ', '.join(sets.Set(words))
'baz, foo, bar'
.>>> words = ["foo",]
.>>> ', '.join(sets.Set(words))
'foo'
Kind regards
Berthold
--
[EMAIL PROTECTED] / <http://h�llmanns.de/>
[EMAIL PROTECTED] / <http://starship.python.net/crew/bhoel/>
--
http://mail.python.org/mailman/listinfo/python-list
