[EMAIL PROTECTED] wrote: > Hello, > > I have the need to write the equivalent of Python class methods in C++. > > Chuck Allison proposes the following > (http://www.artima.com/cppsource/simple.html): > #include <iostream> > using namespace std; > > // A base class that provides counting > template<class T> class Counted { > static int count; > public: > Counted() { ++count; } > Counted(const Counted<T>&) { ++count; } > ~Counted() { --count; } > static int getCount() { return count; } > > }; > > template<class T> int Counted<T>::count = 0; > > // Curious class definitions > class CountedClass : public Counted<CountedClass> {}; > class CountedClass2 : public Counted<CountedClass2> {}; > > It apparently works but in fact it doesn't: > If you derive from such a class, you get the count of the parent class, > > not of the derived class. > class CountedClass3 : public CountedClass {}; > > int main() { > CountedClass a; > cout << CountedClass::getCount() << endl; // 1 > CountedClass b; > cout << CountedClass::getCount() << endl; // 2 > CountedClass3 c; > cout << CountedClass3::getCount() << endl; // 3 and should be 1 > cout << CountedClass::getCount() << endl; // 3 and should be 2 > > } > > I am no C++ expert but i guess there might be some in the Python and > C++ newsgroups. > > Alain >
Why don't you post the Python code you want to "translate" ? Here, I just don't know what you want to achieve !! Pierre -- http://mail.python.org/mailman/listinfo/python-list
