> -----Original Message-----
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED]
g] On Behalf Of [EMAIL PROTECTED]
> Sent: Thursday, July 27, 2006 5:51 PM
> Subject: How do you implement this Python idiom in C++
>
> I am no C++ expert but i guess there might be some in the Python and
> C++ newsgroups.
You could try sth. like this:
<cpp>
#include <iostream>
template<class T> class Counted {
static int count;
public:
Counted() { ++count; }
Counted(const Counted<T>&) { ++count; }
~Counted() { --count; }
template <class V> friend int getCount(V&);
};
template<class T> int Counted<T>::count = 0;
// Curious class definitions
class CountedClass : private Counted<CountedClass> {};
class CountedClass2 : private Counted<CountedClass2> {};
class CountedClass3 : public CountedClass, private Counted<CountedClass3> {};
template <class T>
int getCount(T &)
{
return Counted<T>::count;
}
using namespace std;
int main() {
CountedClass a;
cout << getCount(a) << endl; // 1
CountedClass b;
cout << getCount(b) << endl; // 2
CountedClass3 c;
cout << getCount(c) << endl; // 1
cout << getCount(a) << endl; // 3 and should be 2??
}
</cpp>
Your last assertion ('should be 2') is questionable, IMHO. I think the above
code has it right in this case rather than your python version (after all c isA
CountedClass, isn't it?).
cheers,
aa
--
Andreas Ames | Programmer | Comergo GmbH |
Voice: +49 69 7505 3213 | ames AT avaya DOT com
--
http://mail.python.org/mailman/listinfo/python-list
