> s = re.sub(r'([A-Z]+)([A-Z][a-z])', "\1_\2", s) > s = re.sub(r'([a-z\d])([A-Z])', "\1_\2", s) > i expect to get: > hello_world19_foo_bar > > but instead i get: > hell☺_☻orld19_fo☺_☻ar
Looks like you need to be using "raw" strings for your replacements as well: s = re.sub(r'([A-Z]+)([A-Z][a-z])', r"\1_\2", s) s = re.sub(r'([a-z\d])([A-Z])', r"\1_\2", s) This should allow the backslashes to be parsed as backslashes, not as escape-sequences (which in this case are likely getting interpreted as octal numbers) -tkc -- http://mail.python.org/mailman/listinfo/python-list
