> For the purposes of this question, the list will be: > > t = [ "a", "b", "c", "n", "a", "a", "t", "t", "t" ] > > Now, I know that every 3rd element of the list belongs together: > > Group 1 = 0, 3, 6 > Group 2 = 1, 4, 7 > Group 3 = 2, 5, 8 > > I'm trying to sort this list out so that I get a list of lists that > contain the correct elements: > > Goal = [ [ "a", "n", "t"], [ "b", "a", "t"], > ["c", "a", "t" ] ]
Well, the following worked for me: >>> t = [ "a", "b", "c", "n", "a", "a", "t", "t", "t" ] >>> stride = 3 >>> Goal = [t[i::stride] for i in range(stride)] >>> Goal [['a', 'n', 't'], ['b', 'a', 't'], ['c', 'a', 't']] Or, if you like, in this example: >>> [''.join(t[i::stride]) for i in range(stride)] ['ant', 'bat', 'cat'] if that's of any use. -tkc -- http://mail.python.org/mailman/listinfo/python-list
