I ran into an odd little edge case while experimenting with functions that
create classes on the fly (don't ask me why):
>>> def f(x):
... class C(object):
... x = x
... print C.x
...
>>> f(5)
Traceback (most recent call last):
File "<stdin>", line 1, in ?
File "<stdin>", line 2, in f
File "<stdin>", line 3, in C
NameError: name 'x' is not defined
"x" clearly is defined, but apparently Python is not looking at the nested
variable scope to find it. What's stranger is that if I rename the parameter
"x" to "y", the error goes away:
>>> def f(y):
... class C(object):
... x = y
... print C.x
...
>>> f(5)
5
So, it's not like nested scopes aren't supported in the class block. Rather,
when it sees "x = x", it seems like Python is determining at that point that
"x" is a class variable, and refuses to search any further.
At the top-level, it works as expected:
>>> x = 5
>>> class C(object):
... x = x
...
>>> C.x
5
Any implementation gurus have some insight into what's going on here?
--
.:[ dave benjamin: ramen/[sp00] -:- spoomusic.com -:- ramenfest.com ]:.
"talking about music is like dancing about architecture."
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