Er, whoops. That would work if the last item in the list was 10 (and, of course, this doesn't work for any arbitrary sequence). Is there any "look-ahead" function for list comprehensions?
Danny [EMAIL PROTECTED] wrote: > Simple list comprehension? > > >>> l = [1,2,3,4,5,6,7,8,9,0] > >>> [(x, x+1) for x in l if x%2 == 1] > [(1, 2), (3, 4), (5, 6), (7, 8), (9, 10)] > > Danny > > Neal Becker wrote: > > George Sakkis wrote: > > > > > [EMAIL PROTECTED] wrote: > > > > > >> def transform(seq, size): > > >> i = 0 > > >> while i < len(seq): > > >> yield tuple(seq[i:i+size]) > > >> i += size > > > > > > Or for arbitrary iterables, not just sequences: > > > > > > from itertools import islice > > > def transform(iterable, size): > > > it = iter(iterable) > > > while True: > > > window = tuple(islice(it,size)) > > > if not window: > > > break > > > yield window > > > > > > George > > > > > > > Thanks guys! > > > > This one above is my personal favorite. -- http://mail.python.org/mailman/listinfo/python-list
