Seeing as there doesn't seem to be a good answer to this (or at least not one that we have so far some up with) I have decided to fall back to my old friend the unix shell. It's as portable as python, but is very flexible and fast at doing real things and will tell me if another process by this name is running. If so, print msg and exit. simple.
-h Hari Sekhon MaR wrote: > A very brutal but simple and effective method is to bind() to a socket > on localhost eg (127.0.0.1, 4711), listen() but never accept(). > Any other process trying to to bind() on the same port will fail.. > When the process dies, the port is released automatically, pending som > timedelay.. > > But this assumes you have an execution environment where this is > acceptable. A sysadmin may have objections ;o) > > -- http://mail.python.org/mailman/listinfo/python-list
