Hi
this exaple:
def lcl():
n=1
x=locals()
x["n"]=100
print "n in lcl() is:" +str(n)
#This will say Name error
#x["new"]=1
#print new
n=1
x=globals()
x["n"]=100
print "gobal n is:" +str(n)
x["new"]=1
print "new is:" +str(new)
lcl()
produces
gobal n is:100
new is:1
n in lcl() is:1
shouldn't be n in lcl() 100 too?
why accessing the names dictionary globals() and locals() gives
different results?
This example was made using
Python 2.4.3 (#69, Mar 29 2006, 17:35:34) [MSC v.1310 32 bit (Intel)] on win32
PAolo
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