Hi Tom. Tom Plunket wrote:
> I'd like to figure out if a given parameter is a function or not. > > E.g. > >>>> type(1) > <type 'int'> >>>> type(1) == int > True > > implies: > >>>> def foo(): > ... pass > ... >>>> type(foo) > <type 'function'> >>>> type(foo) == function > Traceback (most recent call last): > File "<stdin>", line 1, in ? > NameError: name 'function' is not defined > > Is there a way I can know if 'foo' is a function? The type of a function is types.FunctionType: >>> import types >>> types.FunctionType <type 'function'> >>> def f(): pass ... >>> type(f) <type 'function'> >>> type(f) is types.FunctionType True However, this doesn't take into account methods (MethodType and UnboundMethodType). In dynamically-typed languages in general, explicit typechecks are not a good idea, since they often preclude user-defined objects from being used. Instead, try performing the call and catch the resulting TypeError: >>> f = 'asdf' >>> try: ... f() ... except TypeError: ... print "oops, f is not callable" ... oops, f is not callable -- Erik Max Francis && [EMAIL PROTECTED] && http://www.alcyone.com/max/ San Jose, CA, USA && 37 20 N 121 53 W && AIM, Y!M erikmaxfrancis There are not fifty ways of fighting, there is only one: to be the conqueror. -- Andrew Malraux, 1937 -- http://mail.python.org/mailman/listinfo/python-list
