> Karl, > > Usually when using this idiom, fun_basket would return a tuple of all of the > defined functions, rather than one vs. the other. So in place of: >> if f == 1: >> return f1 >> if f == 2: >> return f2 > Just do >> return f1, f2 > (For that matter, the argument f is no longer needed either.) > > Then your caller will get 2 functions, who share a common var. You don't > call fun_basket any more, you've already created your two "closures". Call > fun_basket using something like: > > z1,z2 = fun_basket(None) > > And then call z1() and z2() at your leisure - they should have the desired > behavior. > > -- Paul
Thanks a lot Paul and for the other answers. The things are now clear to me. In fact, in the Lisp example that I mentioned, you get a list (or let it be association list) of the internal functions. Then you can call them separately and they work as you expect but it's due to the fact only that you got them created at the same time. -- http://mail.python.org/mailman/listinfo/python-list
