On Dec 20, 7:40 am, durumdara <[EMAIL PROTECTED]> wrote:
> Hi!
>
> I want to replace some seqs. in a html.
> Let:
> a-
> b
> = ab
>
> but:
> xxx -
> b
> must be unchanged, because it is not word split.
>
> I want to search and replace with re, but I don't know how to neg. this
> set ['\ \n\t'].
>
> This time I use full set without these chars, but neg. is better and
> shorter.
>
> Ok, I can use [^\s], but I want to know, how to neg. set of chars.
> sNorm1= '([^[\ \t\n]]{1})\-\<br\ \/\>\n' - this is not working.
>
> Thanks for the help:
> dd
>
> sNorm1= '([%s]{1})\-\<br\ \/\>\n'
> c = range(0, 256)
> c.remove(32)
> c.remove(13)
> c.remove(10)
> c.remove(9)
> s = ["\\%s" % (hex(v).replace('00x', '')) for v in c]
> sNorm1 = sNorm1 % ("".join(s))
> print sNorm1
>
> def Normalize(Text):
>
> rx = re.compile(sNorm1)
> def replacer(match):
> return match.group(1)
> return rx.sub(replacer, Text)
>
> print Normalize('a -<br />\nb')
> print Normalize('a-<br />\nb')
> sys.exit()
It looks like you are trying to de-hyphenate words that have been
broken across line breaks.
Well, this isn't a regexp solution, it uses pyparsing instead. But
I've added a number of other test cases which may be problematic for an
re.
-- Paul
from pyparsing import makeHTMLTags,Literal,Word,alphas,Suppress
brTag,brEndTag = makeHTMLTags("br")
hyphen = Literal("-")
hyphen.leaveWhitespace() # don't skip whitespace before matching this
collapse = Word(alphas) + Suppress(hyphen) + Suppress(brTag) \
+ Word(alphas)
# define action to replace expression with the word before hyphen
# concatenated with the word after the <BR> tag
collapse.setParseAction(lambda toks: toks[0]+toks[1])
print collapse.transformString('a -<br />\nb')
print collapse.transformString('a-<br />\nb')
print collapse.transformString('a-<br/>\nb')
print collapse.transformString('a-<br>\nb')
print collapse.transformString('a- <BR clear=all>\nb')
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