"Dave Borne" <[EMAIL PROTECTED]> wrote in
news:[EMAIL PROTECTED]:
> Thanks, Paul. I didn't know about textwrap, that's neat.
>
> Leon,
> so in my example change
>> data1= [testdata[x:x+colwidth] for x in
>> range(0,len(testdata),colwidth)]
> to
>> data1 = textwrap.wrap(testdata,colwidth)
>> data1 = [x.ljust(colwidth) for x in data1]
>
> oh and I made a mistake that double spaces it. the "print '\n'"
> line needs to be either
> print ''
> or
> print '\n',
> (with a comma)
>
The solutions so far serve up text that is split within the
confines of the column width, but leave a "ragged right" margin,
where the line lengths appear to differ. I had the impression that
the OP wanted right-and-left justified text, such as would
typically be found in a newspaper column. Here's a shot at doing
that for fixed-width fonts. To use it, first split your lines as
others have suggested, then print aline(line,colwid) for each line
in your data.
# aline - align text to fit in specified width
# This module arbitrarily chooses to operate only on long-enough
# lines, where "long-enough" is defined as 60% of the specified
# width in this case.
#
def aline(line, wid):
line = line.strip()
lnlen = len(line)
if wid > lnlen > wid*0.6:
ls = line.split()
diff = wid - lnlen
#nspaces = len(ls)-1
eix = 1
bix = 1
while diff > 0: # and nspaces > 0:
if len(ls[bix]) == 0 or ls[bix].find(' ') >= 0:
ls[bix] += ' '
else:
ls.insert(bix,'')
diff -= 1
bix += 2
if bix >= 1+len(ls)/2: bix = 1
if diff > 0:
if len(ls[-eix]) == 0 or ls[-eix].find(' ') >= 0:
ls[-eix] += ' '
else:
ls.insert(-eix,'')
diff -= 1
eix += 2
if eix >= 1+len(ls)/2: eix = 1
line = ' '.join(ls)
return line
--
rzed
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