On Wed, 27 Dec 2006, Erik Johnson wrote: > "eldorado" <[EMAIL PROTECTED]> wrote in message > news:[EMAIL PROTECTED] >> Hello, >> >> I am trying to get python to give me the PID of a process (in this case >> HUB). I have it working, except for the fact that the output includes >> \012 (newline). Is there a way to ask python not to give me a newline? >> >> Python 1.4 (Oct 14 1997) [C] >> Copyright 1991-1995 Stichting Mathematisch Centrum, Amsterdam >>>>> import os >>>>> g = os.popen("ps -ef | grep HUB | grep -v grep | awk '{ print $2 }'") >>>>> h = g.readlines() >>>>> g.close() >>>>> h >> ['87334\012'] > > > There's more than one way to do it! (Oh, sorry, that's Perl...) > > The two most standard ways would be to call strip() on your string to get > one sans both leading and trialing whitespace > > print h.strip() > > or if you know exactly what you've got (i.e., the newline you don't want is > just the last character), you can just get rid of it: > > h = h[:-1] >
Thanks for the help, however it doesnt look like those two solutions quite work: >>> g = os.popen("ps -ef | grep HUB | grep -v grep | awk '{ print $2 }'") >>> h = g.readlines() >>> g.close() >>> h ['87334\012'] >>> h = h[:-1] >>> h [] >>> >>> import string >>> g = os.popen("ps -ef | grep HUB | grep -v grep | awk '{ print $2 }'") >>> h = g.readlines() >>> g.close() >>> print h.strip() File "<stdin>", line 1 print h.strip() ^ SyntaxError: invalid syntax I looked up the syntax for print and it looks correct (at least to me ;) -- Randomly generated signature You can go anywhere you want if you look serious and carry a clipboard. -- http://mail.python.org/mailman/listinfo/python-list